16x^2+48xy+32y^2=0

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Solution for 16x^2+48xy+32y^2=0 equation:


Simplifying
16x2 + 48xy + 32y2 = 0

Reorder the terms:
48xy + 16x2 + 32y2 = 0

Solving
48xy + 16x2 + 32y2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '16'.
16(3xy + x2 + 2y2) = 0

Factor a trinomial.
16((x + y)(x + 2y)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(x + y)' equal to zero and attempt to solve: Simplifying x + y = 0 Solving x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 x + 0 = 0 + -1y x = 0 + -1y Remove the zero: x = -1y Simplifying x = -1y

Subproblem 2

Set the factor '(x + 2y)' equal to zero and attempt to solve: Simplifying x + 2y = 0 Solving x + 2y = 0 Move all terms containing x to the left, all other terms to the right. Add '-2y' to each side of the equation. x + 2y + -2y = 0 + -2y Combine like terms: 2y + -2y = 0 x + 0 = 0 + -2y x = 0 + -2y Remove the zero: x = -2y Simplifying x = -2y

Solution

x = {-1y, -2y}

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